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#859440 - 12/30/12 06:56 PM Roman Holiday
Pandora Offline
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Some members of the Roman numerals below want to take a holiday, but they don't want to cause any of the equations to become untrue. Remove one line segment from each side of the equal sign so that the resulting equation remains true. (When you remove one line from a V or an X, you may rotate the remaining line slightly.)

-1. II x VII = XIV
-2. LIX = LXII - III
-3. VIII x IX = LXXII
-4. VII x IX = LI + XII
-5. VII x XI = LXXXV - VIII
-6. II x XXXI = XLV + XVII
-7. II x XIV = XXVI + II
-8. II x III x XVII = LX + XLII
-9. IV x XIX = LXXXI - V
-10. III x XXIX = XL + XLVII

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#859452 - 12/30/12 08:35 PM Re: Roman Holiday [Re: Pandora]
CanukDenis Offline
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Registered: 11/26/00
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Loc: Ottawa Ontario Canada
1. II x VII = XIV
II x -II = -IV

Removed line segment from the V and X,
and arranged remaining line segment into a minus sign:
is that ok?
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#859459 - 12/30/12 10:11 PM Re: Roman Holiday [Re: Pandora]
Pandora Offline
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It figures you'd think to do that. lol12 You cannot change the operations in this puzzle, just the operands.
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#859460 - 12/30/12 10:19 PM Re: Roman Holiday [Re: Pandora]
Flo NS Offline
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Registered: 04/11/06
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5. VII x XI = LXXXV - VIII

7x11(77) = 85-8(77)

Isn't this already true? I must not be understanding something.


Edited by Flo NS (12/30/12 10:22 PM)

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#859461 - 12/30/12 10:36 PM Re: Roman Holiday [Re: Pandora]
Pandora Offline
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Registered: 08/06/00
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Loc: Upstate NY
Yes, all of the equations start out true. You must remove a line from each side and still have a true (but different) equation.
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#859464 - 12/30/12 11:06 PM Re: Roman Holiday [Re: Pandora]
Sondi Offline
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3. VII x IX = LXIII headscratch (I think!?)

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#859467 - 12/30/12 11:44 PM Re: Roman Holiday [Re: Pandora]
CCbomber Offline
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8. II x III x XVII = LX + XLII

I x III x XVII = IX + XLII (=51) smile12

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#859472 - 12/31/12 12:01 AM Re: Roman Holiday [Re: Pandora]
CanukDenis Offline
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Registered: 11/26/00
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Originally Posted By: Pandora
You cannot change the operations in this puzzle, just the operands.

But I didn't change the operations: the "x" is still there;
changing VII to -II is changing the operand from 7 to -2


1. II x VII = XIV
II x VI = XII ; the V on right becomes a I

I think that's the answer you expect.
But I prefer my original yes
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#859477 - 12/31/12 01:19 AM Re: Roman Holiday [Re: Pandora]
manxman Offline
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Registered: 07/23/02
Posts: 11326
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9. IV x XIX = LXXXI - V
IV x XX = LXXXI - I grin12
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#859491 - 12/31/12 05:37 AM Re: Roman Holiday [Re: Pandora]
Lex Offline
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2. LX = LXII - II kissy12 (I'm kissing ass and doing it right!)
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#859509 - 12/31/12 10:06 AM Re: Roman Holiday [Re: Pandora]
Flo NS Offline
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Registered: 04/11/06
Posts: 3738
Loc: Nova Scotia
thanks Pandora.

I'll stick with #5.

VII x XI = LXXXV - VIII

VI x XI = LXXIV - VIII

6x11=66 = 74-8 =66

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#859510 - 12/31/12 10:08 AM Re: Roman Holiday [Re: Pandora]
Pandora Offline
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Registered: 08/06/00
Posts: 43959
Loc: Upstate NY
Excellent answers! Denis, I'll give you extra credit for creativity. And you're a good kisser Lex. thumbsup12
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#859532 - 12/31/12 11:46 AM Re: Roman Holiday [Re: Pandora]
CanukDenis Offline
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Registered: 11/26/00
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Originally Posted By: Pandora
And you're a good kisser Lex. thumbsup12

YUK!! Stay away from me!!
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#859541 - 12/31/12 12:14 PM Re: Roman Holiday [Re: Pandora]
butterflybabe Offline
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Registered: 07/27/05
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Loc: Niles, IL
4: VI x IX = LI + III = 54
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#859547 - 12/31/12 12:35 PM Re: Roman Holiday [Re: Pandora]
Pandora Offline
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Registered: 08/06/00
Posts: 43959
Loc: Upstate NY
Good solve, Annette! smile12
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