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#873397 - 03/12/13 02:18 PM Maths Fun(?)
Urban Worrier Online   happy

Graduate Boomer

Registered: 11/16/04
Posts: 16668
Loc: Bucks, England
-1. Draw a regular hexagon then draw the six "alternate" vertices. (Skip one vertex - 1 to 3, 2 to 4 etc). If the area of the original hexagon is 6, what is the area of the internal hexagon that is formed?

-2. Inscribe a square in a circle of radius R. Draw an arc from one corner of the square with radius equal to the side of the square. The area formed between this arc and the circle is a crescent. Find the area of this crescent in terms of R.

-3. In the equations below, replace each letter with a number from 1 to 9, using each number only once:

a/b + c/12 = 1 1/12
d/e + 5/f = 7/8
g/h + 3/i = 1 1/2
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#873457 - 03/12/13 04:38 PM Re: Maths Fun(?) [Re: Urban Worrier]
manxman Offline
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Registered: 07/23/02
Posts: 19878
Loc: Unionville
2. 1\2*R^2 wave
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#873480 - 03/12/13 06:28 PM Re: Maths Fun(?) [Re: Urban Worrier]
CCbomber Offline
BAAG Specialist

Registered: 01/16/03
Posts: 5301
Loc: Mojave desert, California
3.

2/3 + 5/12 = 1 1/12
1/4 + 5/8 = 7/8
7/6 + 3/9 = 1 1/2

smile

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#873586 - 03/13/13 11:21 AM Re: Maths Fun(?) [Re: Urban Worrier]
CanukDenis Online   content
Graduate Boomer

Registered: 11/26/00
Posts: 17522
Loc: Ottawa Ontario Canada
1. Draw a regular hexagon then draw the six "alternate" vertices.
(Skip one vertex - 1 to 3, 2 to 4 etc). If the area of the original hexagon is 6,
what is the area of the internal hexagon that is formed?

So I don't have to type "sqrt(3)"!):
u = sqrt(3)
v = 1/u (ratio radii outer:inner)

R = outer radius
Pentagon area: 3u(R^2) / 2

Given: area = 6 ; soooooo:
3u(R^2) / 2 = 6
R = sqrt(4 / u) : ~1.5196....

r = inner radius
r = R * v : ~.8773....
area = 3u(r^2)/2
area = (drum rolls!) 2 exactement.






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#873654 - 03/13/13 06:30 PM Re: Maths Fun(?) [Re: Urban Worrier]
Urban Worrier Online   happy

Graduate Boomer

Registered: 11/16/04
Posts: 16668
Loc: Bucks, England
CCb - very nice!

Denis - good solve. It can be done by similar triangles. The inner hexagon contains 6 identically-sized equilateral triangles and the outer hexagon contains these 6 plus 6 more plus 12 halves for a total of 18 triangles. Thus, the area of the outer hexagon is 3 times the area of the inner one. smile

manxman - if I read your answer correcly (one over 2 R-squared) then we beg to differ. What's your working? think
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"Women who carry a little extra weight tend to live longer than the men who mention it." - Mrs Worrier

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#873701 - 03/13/13 11:45 PM Re: Maths Fun(?) [Re: Urban Worrier]
manxman Offline
Graduate Boomer

Registered: 07/23/02
Posts: 19878
Loc: Unionville
Sorry, checked my work over and got R^2 smile


Edited by manxman (03/14/13 07:32 AM)
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Sometimes lost is where you need to be. Just because you don't know your direction doesn't mean you don't have one.

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#873814 - 03/14/13 01:26 PM Re: Maths Fun(?) [Re: Urban Worrier]
Urban Worrier Online   happy

Graduate Boomer

Registered: 11/16/04
Posts: 16668
Loc: Bucks, England
Great solve! grin
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