GB HOMEPAGE

It's your move!

Posted By: CanukDenis

It's your move! - 10/01/13 02:13 AM

II = VI

Move one I to end up with both sides equal.
Ya ain't allowed to tinker with the = sign!

2 solutions.

Posted By: manxman

Re: It's your move! - 10/01/13 02:32 AM

move an I from the left side and put it over the I on the right side to get

I=sqrt I wave
Posted By: CanukDenis

Re: It's your move! - 10/01/13 04:05 AM

Correct.

2nd solution anyone?
Posted By: BobH

Re: It's your move! - 10/01/13 04:25 AM

How about, I = I V I, where V is the logical OR operator.
Posted By: CanukDenis

Re: It's your move! - 10/01/13 11:41 AM

Not mine Bob; but shrewd!
However, as logical operator, doesn't the "V"
have a horizontal line underneath?
V
-
Posted By: BobH

Re: It's your move! - 10/01/13 12:03 PM

Not that I recall seeing, Denis. Take a look here: Wikipedia - Logical Connective.

But now I will be looking for another solution. smile
Posted By: CanukDenis

Re: It's your move! - 10/01/13 03:51 PM

Hmmm...also used wikipedia:

http://en.wikipedia.org/wiki/List_of_logic_symbols
Posted By: soot

Re: It's your move! - 10/01/13 05:58 PM

whoa!

wave
Posted By: CanukDenis

Re: It's your move! - 10/01/13 06:12 PM

Worry not Soot; solution is tricky, but quite simple:
no strange characters/representations involved.

Hint: the "move" is on right side only, so II = ?
Posted By: manxman

Re: It's your move! - 10/01/13 08:37 PM

VI becomes XI which is eleven
II is also eleven smile
Posted By: BobH

Re: It's your move! - 10/01/13 08:55 PM

Hi Denis, the underline indicates an exclusive OR rather than a "normal" OR. I may have actually seen that back in my college days but don't remember. smile

Manxman, how do you do that?

Click to reveal..
I guess you could break the V apart into two I's and then lay one on top of the other, or you could move the I on the far right on top of the left side of the V and make a sort of slanted and connected XI. Anyway, very clever! thumbsup
Posted By: CanukDenis

Re: It's your move! - 10/01/13 10:31 PM

Yep; II = XI was what I was looking for.
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