Roman Holiday
#859440
12/30/12 07:56 PM
12/30/12 07:56 PM
|
Joined: Aug 2000
Posts: 52,983 Upstate NY
Pandora
OP
Sonic Boomer
|
OP
Sonic Boomer
Joined: Aug 2000
Posts: 52,983
Upstate NY
|
Some members of the Roman numerals below want to take a holiday, but they don't want to cause any of the equations to become untrue. Remove one line segment from each side of the equal sign so that the resulting equation remains true. (When you remove one line from a V or an X, you may rotate the remaining line slightly.) -1. II x VII = XIV -2. LIX = LXII - III -3. VIII x IX = LXXII -4. VII x IX = LI + XII -5. VII x XI = LXXXV - VIII -6. II x XXXI = XLV + XVII -7. II x XIV = XXVI + II -8. II x III x XVII = LX + XLII -9. IV x XIX = LXXXI - V -10. III x XXIX = XL + XLVII
The moon is actually more useful than the sun since the moon gives us light at night when it's dark. The sun only gives us light during the day when it's already bright out.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859452
12/30/12 09:35 PM
12/30/12 09:35 PM
|
Joined: Nov 2000
Posts: 18,719 Ottawa Ontario Canada
CanukDenis
Graduate Boomer
|
Graduate Boomer
Joined: Nov 2000
Posts: 18,719
Ottawa Ontario Canada
|
1. II x VII = XIV II x -II = -IV
Removed line segment from the V and X, and arranged remaining line segment into a minus sign: is that ok?
I'm a man of few words, BUT I use 'em often!!
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859459
12/30/12 11:11 PM
12/30/12 11:11 PM
|
Joined: Aug 2000
Posts: 52,983 Upstate NY
Pandora
OP
Sonic Boomer
|
OP
Sonic Boomer
Joined: Aug 2000
Posts: 52,983
Upstate NY
|
It figures you'd think to do that. You cannot change the operations in this puzzle, just the operands.
The moon is actually more useful than the sun since the moon gives us light at night when it's dark. The sun only gives us light during the day when it's already bright out.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859460
12/30/12 11:19 PM
12/30/12 11:19 PM
|
Joined: Apr 2006
Posts: 4,944 Nova Scotia
Flo NS
Addicted Boomer
|
Addicted Boomer
Joined: Apr 2006
Posts: 4,944
Nova Scotia
|
5. VII x XI = LXXXV - VIII
7x11(77) = 85-8(77)
Isn't this already true? I must not be understanding something.
Last edited by Flo NS; 12/30/12 11:22 PM.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859461
12/30/12 11:36 PM
12/30/12 11:36 PM
|
Joined: Aug 2000
Posts: 52,983 Upstate NY
Pandora
OP
Sonic Boomer
|
OP
Sonic Boomer
Joined: Aug 2000
Posts: 52,983
Upstate NY
|
Yes, all of the equations start out true. You must remove a line from each side and still have a true (but different) equation.
The moon is actually more useful than the sun since the moon gives us light at night when it's dark. The sun only gives us light during the day when it's already bright out.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859472
12/31/12 01:01 AM
12/31/12 01:01 AM
|
Joined: Nov 2000
Posts: 18,719 Ottawa Ontario Canada
CanukDenis
Graduate Boomer
|
Graduate Boomer
Joined: Nov 2000
Posts: 18,719
Ottawa Ontario Canada
|
You cannot change the operations in this puzzle, just the operands. But I didn't change the operations: the "x" is still there; changing VII to -II is changing the operand from 7 to -2 1. II x VII = XIV II x VI = XII ; the V on right becomes a I I think that's the answer you expect. But I prefer my original
I'm a man of few words, BUT I use 'em often!!
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859477
12/31/12 02:19 AM
12/31/12 02:19 AM
|
Joined: Jul 2002
Posts: 29,125 Unionville
manxman
Sonic Boomer
|
Sonic Boomer
Joined: Jul 2002
Posts: 29,125
Unionville
|
9. IV x XIX = LXXXI - V IV x XX = LXXXI - I
Sometimes lost is where you need to be. Just because you don't know your direction doesn't mean you don't have one.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859491
12/31/12 06:37 AM
12/31/12 06:37 AM
|
Joined: Mar 2004
Posts: 11,887 Isle of Man
Lex
Adept Boomer
|
Adept Boomer
Joined: Mar 2004
Posts: 11,887
Isle of Man
|
2. LX = LXII - II (I'm kissing ass and doing it right!)
Life is what happens while you're making other plans.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859578
12/31/12 04:50 PM
12/31/12 04:50 PM
|
Joined: Sep 2002
Posts: 13,701 Virginia
Jema
Adept Boomer
|
Adept Boomer
Joined: Sep 2002
Posts: 13,701
Virginia
|
7. II x XIV = XXVI + II (2 x 14 = 26 + 2) II x IX = XVI + II (2 x 9 = 16 + 2) Couldn't #1 just simply be II x II = IV?
Wouldn't that jar your mustard!
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859584
12/31/12 05:29 PM
12/31/12 05:29 PM
|
Joined: Aug 2000
Posts: 52,983 Upstate NY
Pandora
OP
Sonic Boomer
|
OP
Sonic Boomer
Joined: Aug 2000
Posts: 52,983
Upstate NY
|
Jema, you show two equations but you rearranged the numerals. This puzzle requires you to subtract one line from each side of the equation. And yes, your #1 would work if you removed two lines from each side.
The moon is actually more useful than the sun since the moon gives us light at night when it's dark. The sun only gives us light during the day when it's already bright out.
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859587
12/31/12 06:42 PM
12/31/12 06:42 PM
|
Joined: Sep 2002
Posts: 13,701 Virginia
Jema
Adept Boomer
|
Adept Boomer
Joined: Sep 2002
Posts: 13,701
Virginia
|
OK. I misunderstood what "Remove one line segment from each side of the equal sign ..." meant. How about 7. II x XII = XXII + II (2 x 12 = 22 + 2)? On each side of = the V becomes I.
Wouldn't that jar your mustard!
|
|
|
Re: Roman Holiday
[Re: Pandora]
#859590
12/31/12 07:36 PM
12/31/12 07:36 PM
|
Joined: Jul 2002
Posts: 29,125 Unionville
manxman
Sonic Boomer
|
Sonic Boomer
Joined: Jul 2002
Posts: 29,125
Unionville
|
10. III x XXIX = XL + XLVII II x XXIX = XI + XLVII
Sometimes lost is where you need to be. Just because you don't know your direction doesn't mean you don't have one.
|
|
|
|
|